Algebraic Structures and Their ApplicationsAlgebraic Structures and Their Applications
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Sat, 20 Oct 2018 10:40:57 +0100FeedCreatorAlgebraic Structures and Their Applications
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Feed provided by Algebraic Structures and Their Applications. Click to visit.An investigation on regular relations of universal hyperalgebras
http://as.yazd.ac.ir/article_1171_237.html
In this paper, by considering the notion of $Sigma$-hyperalgebras for an arbitrary signature $Sigma$, we study the notions of regular and strongly regular relations on a $Sigma$-hyperalgebra, $mathfrak{A}$. We show that each regular relation which contains a strongly regular relation is a strongly regular relation. Then we concentrate on the connection between the fundamental relation of $mathfrak{A}$ and the set of complete parts of $mathfrak{A}$.Sat, 30 Jun 2018 19:30:00 +0100An efficient algorithm for Mixed domination on Generalized Series-Parallel Graphs
http://as.yazd.ac.ir/article_1208_237.html
A mixed dominating set $S$ of a graph $G=(V, E)$ is a subset of vertices and edges like $S subseteq V cup E$ such that each element $vin (V cup E) setminus S$ is adjacent or incident to at least one element in $S$. The mixed domination number $gamma_m(G)$ of a graph $G$ is the minimum cardinality among all mixed dominating sets in $G$. The problem of finding $gamma_{m}(G)$ is known to be NP-complete. In this paper, we present an explicit polynomial-time algorithm using the parse tree to construct a mixed dominating set of size $gamma_{m}(G)$ where $G$ is a generalized series-parallel graph.Sat, 30 Jun 2018 19:30:00 +0100A short Note on prime submodules
http://as.yazd.ac.ir/article_1209_237.html
Let $R$ be a commutative ring with identity and $M$ be a unital $R$-module. A proper submodule $N$ of $M$ with $N:_RM=frak p$ is said to be prime or $frak p$-prime ($p$ a prime ideal of $R$) if $rxin N$ for $rin R$ and $xin M$ implies that either $xin N$ or $rin frak p$. In this paper we study a new equivalent conditions for a minimalprime submodules of an $R$-module to be a finite set, whenever $R$ is a Noetherian ring. Also we introduce the concept of arithmetic rank of a submodule of a Noetherian module and we give an upper bound for it.Sat, 30 Jun 2018 19:30:00 +0100Boolean center of lattice ordered $EQ$-algebras with bottom element
http://as.yazd.ac.ir/article_1210_237.html
In this paper, some new properties of $EQ$-algebras are investigated. We introduce and study the notion of Boolean center of lattice ordered $EQ$-algebras with bottom element. We show that in a good $ell EQ$-algebra $E$ with bottom element the complement of an element is unique. Furthermore, Boolean elements of a good bounded lattice $EQ$-algebra are characterized. Finally, we obtain conditions under which Boolean center of an $EQ$-algebra $E$ is the subalgebra of $E$. Sat, 30 Jun 2018 19:30:00 +0100On endo-semiprime and endo-cosemiprime modules
http://as.yazd.ac.ir/article_1211_237.html
In this paper, we study the notions of es~ and ec~ modules and obtain some related results. For instance,we show that in a right self-injective ring $R$, all nonzero ideals of $R$ are endo-semiprime as right (left) $R$-modules if and only if $R$ is semiprime. Also, we prove that both being endo-semiprime and being ec~ are Morita invariant properties.Sat, 30 Jun 2018 19:30:00 +0100On dual of the generalized splitting matroids
http://as.yazd.ac.ir/article_1213_237.html
Given a binary matroid $M$ and a subset $Tsubseteq E(M)$, Luis A. Goddyn posed a problem that the dual of the splitting of $M$, i.e., ($(M_{T})^{*}$) is not always equal to the splitting of the dual of $M$, ($(M^{*})_{T}$). This persuade us to ask if we can characterize those binary matroids for which $(M_{T})^{*}=(M^{*})_{T}$. Santosh B. Dhotre answered this question for a two-element subset $T$. In this paper, we generalize his result for any subset $Tsubseteq E(M)$ and exhibit a criterion for a binary matroid $M$ and subsets $T$ for which $(M_{T})^{*}$ and $(M^{*})_{T}$ are the equal. We also show that there is no subset $Tsubseteq E(M)$ for which, the dual of element splitting of $M$, i.e., ($(M^{'}_{T})^{*}$) equals to the element splitting of the dual of $M$, (($M^{*})^{'}_{T}$).Sat, 30 Jun 2018 19:30:00 +0100